Mural
painting in a museum

Answer:

As
an example, raw data is following

Monthly income (US$): 2000 2500 3000 3500

Monthly income (US$): 2000 2500 3000 3500

Frequency
: 40 35 20 5

After
data collecting, I did following statistic:

1)
Find the values of :

Median
= Q2

IQR
= Q3-Q1

Qi
= i th quartile

Statistic
values could be found by R program with following codes:

>
x<-c(2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000,
2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000,
2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000,
2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2500, 2500, 2500,
2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500,
2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500,
2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 3000,
3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000,
3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3500, 3500, 3500,
3500, 3500)

>
summary (x)

Output
(Result):

Min.
1st Qu. Median Mean 3rd Qu. Max.

2000
2000 2500 2450 2625 3500

One
of street arts in 3D

From
R output (result):

Median
=2500

IQR
= Q3-Q1 = 2625 – 2000 = 625

To
find outlier:

Median
± 1.5 * IQR

2500
± 1.5 * 625

2500
± 937.5

Math is complicated to me but I do love street art!

ReplyDeleteThank you to visit:

DeleteMATH 1280 Introduction to Statistics – Discussion 3 – Part 2

@

Mural painting in a museum

MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

Delete-

2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR

From R output (result):

Median =2500

IQR = Q3-Q1 = 2625 – 2000 = 625

To find outlier:

Median ± 1.5 * IQR

2500 ± 1.5 * 625

2500 ± 937.5

Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA

Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.

Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

awesome article.

ReplyDeletethanks for sharing and have a nice day :)

Thank you to visit:

DeleteMATH 1280 Introduction to Statistics – Discussion 3 – Part 2

@

Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

Answer:

I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

As an example, raw data is following

Monthly income (US$): 2000 2500 3000 3500

Frequency : 40 35 20 5

After data collecting, I did following statistic:

1) Find the values of :

Median = Q2

IQR = Q3-Q1

Qi = i th quartile

Statistic values could be found by R program with following codes:

> x<-c(2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3500, 3500, 3500, 3500, 3500)

> summary (x)

Output (Result):

Min. 1st Qu. Median Mean 3rd

MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

Delete-

2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR

From R output (result):

Median =2500

IQR = Q3-Q1 = 2625 – 2000 = 625

To find outlier:

Median ± 1.5 * IQR

2500 ± 1.5 * 625

2500 ± 937.5

Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA

Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.

Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

wow those look incredible;)

ReplyDeleteThank you to visit:

DeleteMATH 1280 Introduction to Statistics – Discussion 3 – Part 2

@

One of street arts in 3D

MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

Delete-

Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

Answer:

I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

As an example, raw data is following

Monthly income (US$): 2000 2500 3000 3500

Frequency : 40 35 20 5

I love the street murals, done well, although this one is a museum.

ReplyDeleteThank you to visit:

DeleteMATH 1280 Introduction to Statistics – Discussion 3 – Part 2

@

2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR

From R output (result):

Median =2500

IQR = Q3-Q1 = 2625 – 2000 = 625

To find outlier:

Median ± 1.5 * IQR

2500 ± 1.5 * 625

2500 ± 937.5

Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA

Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.

Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

DeleteCzyli można na tym zarobić :)

ReplyDeleteThank you to visit:

DeleteMATH 1280 Introduction to Statistics – Discussion 3 – Part 2

@

Mural painting in a museum

That street art is awesome.

ReplyDeleteThank you to visit:

DeleteMATH 1280 Introduction to Statistics – Discussion 3 – Part 2

@

Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

Answer:

I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

As an example, raw data is following

Monthly income (US$): 2000 2500 3000 3500

Frequency : 40 35 20 5

MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

DeleteThank you for this example.

ReplyDeleteThank you to visit:

DeleteMATH 1280 Introduction to Statistics – Discussion 3 – Part 2

@

After data collecting, I did following statistic:

1) Find the values of :

Median = Q2

IQR = Q3-Q1

Qi = i th quartile

Statistic values could be found by R program with following codes:

> x<-c(2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3500, 3500, 3500, 3500, 3500)

> summary (x)

Output (Result):

Min. 1st Qu. Median Mean 3rd Qu. Max.

2000 2000 2500 2450 2625 3500