### MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

Mural painting in a museum

Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

As an example, raw data is following
Monthly income (US\$): 2000 2500 3000 3500
Frequency : 40 35 20 5

After data collecting, I did following statistic:
1) Find the values of :
Median = Q2
IQR = Q3-Q1
Qi = i th quartile

Statistic values could be found by R program with following codes:
> x<-c(2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3500, 3500, 3500, 3500, 3500)
> summary (x)

Output (Result):
Min. 1st Qu. Median Mean 3rd Qu. Max.
2000 2000 2500 2450 2625 3500

One of street arts in 3D

2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR
From R output (result):
Median =2500
IQR = Q3-Q1 = 2625 – 2000 = 625

To find outlier:
Median ± 1.5 * IQR
2500 ± 1.5 * 625
2500 ± 937.5
Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA

Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.

Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

1. Math is complicated to me but I do love street art!

1. Thank you to visit:
MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
@
Mural painting in a museum

2. MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
-
2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR

From R output (result):
Median =2500
IQR = Q3-Q1 = 2625 – 2000 = 625

To find outlier:
Median ± 1.5 * IQR
2500 ± 1.5 * 625
2500 ± 937.5

Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA

Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.

Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

2. awesome article.
thanks for sharing and have a nice day :)

1. Thank you to visit:
MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
@
Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

As an example, raw data is following
Monthly income (US\$): 2000 2500 3000 3500
Frequency : 40 35 20 5

After data collecting, I did following statistic:
1) Find the values of :
Median = Q2
IQR = Q3-Q1
Qi = i th quartile

Statistic values could be found by R program with following codes:

> x<-c(2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3500, 3500, 3500, 3500, 3500)

> summary (x)

Output (Result):
Min. 1st Qu. Median Mean 3rd

2. MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
-
2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR

From R output (result):
Median =2500
IQR = Q3-Q1 = 2625 – 2000 = 625

To find outlier:
Median ± 1.5 * IQR
2500 ± 1.5 * 625
2500 ± 937.5

Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA

Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.

Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

3. wow those look incredible;)

1. Thank you to visit:
MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
@
One of street arts in 3D

2. MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
-
Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

As an example, raw data is following
Monthly income (US\$): 2000 2500 3000 3500
Frequency : 40 35 20 5

4. I love the street murals, done well, although this one is a museum.

1. Thank you to visit:
MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
@
2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR

From R output (result):

Median =2500

IQR = Q3-Q1 = 2625 – 2000 = 625

To find outlier:

Median ± 1.5 * IQR

2500 ± 1.5 * 625

2500 ± 937.5

Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA

Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.

Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

2. MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

5. Czyli można na tym zarobić :)

1. Thank you to visit:
MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
@
Mural painting in a museum

6. That street art is awesome.

1. Thank you to visit:
MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
@
Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

As an example, raw data is following
Monthly income (US\$): 2000 2500 3000 3500
Frequency : 40 35 20 5

2. MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

7. Thank you for this example.

1. Thank you to visit:
MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
@
After data collecting, I did following statistic:
1) Find the values of :
Median = Q2
IQR = Q3-Q1
Qi = i th quartile

Statistic values could be found by R program with following codes:

> x<-c(2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3500, 3500, 3500, 3500, 3500)

> summary (x)

Output (Result):

Min. 1st Qu. Median Mean 3rd Qu. Max.

2000 2000 2500 2450 2625 3500