MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

Friday, July 5, 2019
Mural painting in a museum

Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

Answer:
I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

As an example, raw data is following
Monthly income (US$): 2000 2500 3000 3500
Frequency : 40 35 20 5


After data collecting, I did following statistic:
1) Find the values of :
Median = Q2
IQR = Q3-Q1
Qi = i th quartile 


Statistic values could be found by R program with following codes:
> x<-c(2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3500, 3500, 3500, 3500, 3500)
> summary (x)

Output (Result):
Min. 1st Qu. Median Mean 3rd Qu. Max.
2000 2000 2500 2450 2625 3500


One of street arts in 3D

2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR
From R output (result):
Median =2500
IQR = Q3-Q1 = 2625 – 2000 = 625

To find outlier:
Median ± 1.5 * IQR
2500 ± 1.5 * 625
2500 ± 937.5
Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA

Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.

Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

19 comments:

  1. Math is complicated to me but I do love street art!

    ReplyDelete
    Replies
    1. Thank you to visit:
      MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
      @
      Mural painting in a museum

      Delete
    2. MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
      -
      2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR

      From R output (result):
      Median =2500
      IQR = Q3-Q1 = 2625 – 2000 = 625

      To find outlier:
      Median ± 1.5 * IQR
      2500 ± 1.5 * 625
      2500 ± 937.5

      Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA

      Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.

      Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

      Delete
  2. awesome article.
    thanks for sharing and have a nice day :)

    ReplyDelete
    Replies
    1. Thank you to visit:
      MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
      @
      Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

      Answer:
      I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

      As an example, raw data is following
      Monthly income (US$): 2000 2500 3000 3500
      Frequency : 40 35 20 5


      After data collecting, I did following statistic:
      1) Find the values of :
      Median = Q2
      IQR = Q3-Q1
      Qi = i th quartile


      Statistic values could be found by R program with following codes:

      > x<-c(2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3500, 3500, 3500, 3500, 3500)

      > summary (x)



      Output (Result):
      Min. 1st Qu. Median Mean 3rd

      Delete
    2. MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
      -
      2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR

      From R output (result):
      Median =2500
      IQR = Q3-Q1 = 2625 – 2000 = 625

      To find outlier:
      Median ± 1.5 * IQR
      2500 ± 1.5 * 625
      2500 ± 937.5

      Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA

      Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.

      Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

      Delete
  3. Replies
    1. Thank you to visit:
      MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
      @
      One of street arts in 3D

      Delete
    2. MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
      -
      Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

      Answer:
      I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

      As an example, raw data is following
      Monthly income (US$): 2000 2500 3000 3500
      Frequency : 40 35 20 5

      Delete
  4. I love the street murals, done well, although this one is a museum.

    ReplyDelete
    Replies
    1. Thank you to visit:
      MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
      @
      2) Find outlier, where an outlier is that if it lies outside the range of Median ± 1.5 * IQR

      From R output (result):

      Median =2500

      IQR = Q3-Q1 = 2625 – 2000 = 625


      To find outlier:

      Median ± 1.5 * IQR

      2500 ± 1.5 * 625

      2500 ± 937.5

      Thus, no outlier of data (values). The data (values) are the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA


      Finally, however, if I found two values that were twice as big as the next highest value or twice as low as the next lowest values, I will say that these are outliers.


      Then, I may omit these two outliers or I round them off to the maximum permissible by the above range (Median ± 1.5 * IQR).

      Delete
    2. MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

      Delete
  5. Czyli można na tym zarobić :)

    ReplyDelete
    Replies
    1. Thank you to visit:
      MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
      @
      Mural painting in a museum

      Delete
  6. Replies
    1. Thank you to visit:
      MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
      @
      Introduction and questions can be seen at Part 1 (in previous article): MATH 1280 Introduction to Statistics – Discussion 3 – Part 1

      Answer:
      I am interest to know the monthly income of street artists (painters) in my city, Baton Rouge, Louisiana, USA. Then, I sample randomly 100 of them. In this case, variable of interest is monthly income in dollars, as numeric measurement

      As an example, raw data is following
      Monthly income (US$): 2000 2500 3000 3500
      Frequency : 40 35 20 5

      Delete
    2. MATH 1280 Introduction to Statistics – Discussion 3 – Part 2

      Delete
  7. Replies
    1. Thank you to visit:
      MATH 1280 Introduction to Statistics – Discussion 3 – Part 2
      @
      After data collecting, I did following statistic:
      1) Find the values of :
      Median = Q2
      IQR = Q3-Q1
      Qi = i th quartile


      Statistic values could be found by R program with following codes:

      > x<-c(2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 2500, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3000, 3500, 3500, 3500, 3500, 3500)

      > summary (x)



      Output (Result):

      Min. 1st Qu. Median Mean 3rd Qu. Max.

      2000 2000 2500 2450 2625 3500

      Delete